Php Log In If-Else -


मुझे यह कोड है: 

  & lt; php शामिल करें "konek.php"; यदि (isset ($ _ POST ['submit']) {$ schoUsername = $ _POST ['schoUsername']; $ schoPassword = $ _POST ['schoPassword']; $ schoPosition = $ _POST ['schoPosition']; $ पासवर्ड = sha1 ($ schoPassword); $ sql = "SELECT * tblscholar से WHERE schoUsername = '$ schoUsername' और schoPassword = '$ password'"; $ Conn = db_connect (); $ परिणाम = $ conn- & gt; क्वेरी ($ sql); $ row_num = mysqli_num_rows ($ परिणाम); अगर ($ row_num! = 0) {$ sql = "SELECT * tblscholar WHERE schoU नाम = '$ schoUsername' और schoPassword = '$ password'"; $ कनेक्ट = db_connect (); $ Res = $ connect- & gt; क्वेरी ($ sql); $ row_num = mysqli_num_rows ($ res); यदि ($ schoPosition == 'Spiritual_and_Community_Services_Committee_Head') शीर्षलेख ("स्थान: डैशबोर्ड फोरेएससीएच। पीएचपी"); अन्य शीर्षलेख ("स्थान: डैशबोर्डफ़ोरयूसर.एफ़पी"); } और {गूंज "अमान्य"; }}? & gt;   
 यहां konek.php है  
  & lt;? php फ़ंक्शन db_connect () {$ result = new mysqli ('localhost', 'root', '', 'सिमयानन'); यदि (! $ का परिणाम) वापसी झूठी; वापसी का परिणाम; }? & Gt;   
 मैं चाहता हूं कि ऐसा होना चाहिए, यदि आपकी स्थिति व्यवस्थापक है, तो आप सीधे व्यवस्थापक के डैशबोर्ड पर जाएंगे, और जब आपकी स्थिति लाइब्रेरियन है, तो आप सीधे डैशबोर्ड पर जाएं लाइब्रेरियन और इसके विपरीत हर बार जब मैं लॉगिन करता हूं, तो पृष्ठ डैशबोर्डफ़ोसर.एफ़पी   
 
 
 में रीडायरेक्ट हो रहा है प्रवाह को तोड़ने के लिए बाहर निकलें जोड़ें  <पूर्व>  यदि ($ schoPosition == 'Spiritual_and_Community_Services_Committee_Head') शीर्षलेख ("स्थान: डैशबोर्डफ़ोर्ड एससीएच। पीएचपी"); बाहर जाएं(); अन्य शीर्षलेख ("स्थान: डैशबोर्डफ़ोरयूसर.एफ़पी"); बाहर जाएं(); } और {गूंज "अमान्य"; }}? & gt;

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