recursion - Recursive functions with multiple arguments Haskell -


A very simple question: I want to apply multiples of 2 integers in Haskell. I do not compile what I wrote: 

  mult :: int -> Int - & gt; The problem is the last statement I tried to write:   
  
  
 Pre>  mult xy = x + (mult x-1 y)   
 and  
  mult xy = x + (multiplexed by x- 1, y))   
 The error I get is:  
  could not match the expected actual type `int -> Type 'Int' in the IT returns' call type 'multi'   
 I do not know that the compiler says that  mult  come back to a  Goes - & gt; IT  when it explicitly returns  Int .   
 
 
 You have to put  x-1  in parentheses! Like  
  mult xy = x + (mult (x-1) y)   
 By the way, it does not count x and multiply Y: ) Try some examples ... this is just a little mistake.

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