java - Get input field of a dialog in eclipse -


For my plugin, I try to get active eclips communication with these lines: 

  string shelltitle = display.tv (). GetActiveShell () GetTitle (); System.out.println ("Open Dialog:" + Shelltital);   
 If I open the search dialog for example, these lines print me  
  Open Dialog: In my console   < p> Search but I would also like to print the keyword in the search field, for example  
  opened dialog: search (with the search term 'chatation')   
 I have read the API reference and there, I can just get the  getTitle ()  and get some other ways to get the limits.  
 What is my idea? And if not, then is this possible with these so-called expansion points? I have never used them, but have heard about them.   
 
 
 Mistakes in your question:  
     
  1.  Code> getTitle ()  calling the method is wrong.  
  2.  You are mixing dialog and shell   
     Assume that you are talking about Shell. You can use the code below to gain control of the active shell.  
      import org.eclipse.swt.SWT; Import org.eclipse.swt.events.SelectionEvent; Import org.eclipse.swt.events.SelectionListener; Import org.eclipse.swt.layout.FillLayout; Import org.eclipse.swt.widgets.Button; Import org.eclipse.swt.widgets.Control; Import org.eclipse.swt.widgets.Display; Import org.eclipse.swt.widgets.Label; Import org.eclipse.swt.widgets.Shell; Import org.eclipse.swt.widgets.Text; Public square ShellControlsGetting {public static zero main (string [] args) {display display = new display (); Last Shell Shell = New Shell (Display); Shell.setLayout (new FillLayout ()); Button button = new button (shell, SWT.PUSH); Button. Setting Text ("Open 3 Styles"); The last shell [] shells = new shell [3]; button. Add ChainListner (new selection listener) {@ Override Public Wide Widget SelectionEvent} {for (iTunes i = 0; i   
     If you do not answer this question, edit your post, add some code and explain what exactly are you expecting.

Comments

Post a Comment

Popular posts from this blog

c# - ASP.NET MVC - Attaching an entity of type 'MODELNAME' failed because another entity of the same type already has the same primary key value -

In brief, the wrapper module is inserted during posting and the status of an entry is changed to 'modified' . Before changing the state, the state is set to 'separate', but calling attachments () causes the same error to be thrown away. I am using EF 6. Model / wrapper class public class avi model {public A is a {get; Set; } Public listing & lt; B & gt; B {received; Set; } Public cc {receipt; Set; }} Administrator edit public functioning (int? id) {if (id == null) {new HttpStatusCodeResult (HttpStatusCode.BadRequest); } If (! Conveyor Access (id.Value)) new HTTPTitus code result (HTTP status code. Forbidden); Var aViewModel = new AViewModel (); aViewModel.A = db.As.Find (id); If (aViewModel.Receipt == zero) {return HttpNotFound (); } aViewModel.b = db.Bs.Where (x => x.aid == id.Value) .Oolist (); AViewModel.Vendor = db.Cs.Where (x => x.cid == aViewModel.a.cID) .FirstOrDefault (); See Return (aViewModel); } [HTPFost] [Valid AntitiferousTeacon...
Read more

jasper reports - How to center align barcode using jasperreports and barcode4j -

I use iReport 5.5.0 . How to align a barcode component to the center The relevant piece of my jrxml is below & Lt; JR: Code 128 xmlns: JR = "http://jasperreports.sourceforge.net/jasperreports/components" xsi: schemaLocation = "http://jasperreports.sourceforge.net/jasperreports/components http: //jasperreports.sourceforge Purge / xsd / components.xsd "textPosition =" bottom "& gt; & Lt; Jr: codeExpression & gt; & Lt; [CDATA [$ F {number}]] & gt; & Lt; / Jr: codeExpression & gt; & Lt; / Jr: Code 128 & gt; & Lt; / componentElement & gt; "Text" itemprop = "text"> Create a style after this, it is called "barcode", like: & lt; Style name = "barcode" fontName = "Helvetica" fONTSIZE = "10" hAlign = "center" valign = "center" /> and set the property of your barcode element to "barcode".
Read more

django - CommandError: You must set settings.ALLOWED_HOSTS if DEBUG is False -

I use Django 1.6.5 with settings in my program txsite: DEBUG = true I set the lie to debug, but when I get the runner , I get the following error: CommandError: You have to set the settings. OLOWOWHESTS If DEBUG is False I ALLOWED_HOSTS = ['127.0.0.1', 'localhost'] but I get the same error. Does anyone know this address? Try ALLOWED_HOSTS = ['*'] Less secure If you are not on a firewall or public LAN, but what I use and it works. Edit: Interestingly enough, I have to add some of my 1.8 projects, even if DEBUG = True . Why so very uncertain
Read more