Python Merge Dictionary from Mysql Results -


I am trying to merge the output of 7 MySQL queries and merge them into a specific field (first, ID) .

My first initial idea was to get the results of seven questions and put them in the form of a key with the first field and then the balance as the value. 

  returnDict Once I get results in my own Dikts with seven questions, I can combine them. I =============== ================================================== ==== I in one of the following words:  
  for D (first sentence, second decit, third digit, fourth dict, fifth show, sixth appearance, seventh appearance): For the key, value in d.iteritems (): dd [key]. Append (value)   
 Now, the only problem is my When combines the above Code, it does not exclude the original dictionary, it only adds to them, thus creating a very nasty dictionary.  
 This is what it looks like:  
  6: ('blah.net', datetime.datetime (20 11, 6, 23, 0, 0), 4 L, 1 L, datetime.datetime (2011, 6, 23, 0, 0)), ('Foo', 1 L), ('Unknown Foo', 2 L), (datetime   
 This is what I want to see:  
   
  6: 'blah.net', datetime.datetime (2011, 6, 23, 0, 0), 4L, 1L, datetime.datetime (2011, 6, 23, 0, 0), 'Foo', 1 L, 'Unknown Foo', 2 L, Data Timediet (2013, 11, 14, 12, 30, 24), 'Basic Category 3'    
 
 
 The simplest solution Includes using a union query on behalf of the database .  
 If you want to do it in Python, then I will do something like   value for value in   To import the default Detox DD = Default Dict (List First Dict, Second Decit, ...)

Comments

Post a Comment

Popular posts from this blog

c# - ASP.NET MVC - Attaching an entity of type 'MODELNAME' failed because another entity of the same type already has the same primary key value -

In brief, the wrapper module is inserted during posting and the status of an entry is changed to 'modified' . Before changing the state, the state is set to 'separate', but calling attachments () causes the same error to be thrown away. I am using EF 6. Model / wrapper class public class avi model {public A is a {get; Set; } Public listing & lt; B & gt; B {received; Set; } Public cc {receipt; Set; }} Administrator edit public functioning (int? id) {if (id == null) {new HttpStatusCodeResult (HttpStatusCode.BadRequest); } If (! Conveyor Access (id.Value)) new HTTPTitus code result (HTTP status code. Forbidden); Var aViewModel = new AViewModel (); aViewModel.A = db.As.Find (id); If (aViewModel.Receipt == zero) {return HttpNotFound (); } aViewModel.b = db.Bs.Where (x => x.aid == id.Value) .Oolist (); AViewModel.Vendor = db.Cs.Where (x => x.cid == aViewModel.a.cID) .FirstOrDefault (); See Return (aViewModel); } [HTPFost] [Valid AntitiferousTeacon...
Read more

jasper reports - How to center align barcode using jasperreports and barcode4j -

I use iReport 5.5.0 . How to align a barcode component to the center The relevant piece of my jrxml is below & Lt; JR: Code 128 xmlns: JR = "http://jasperreports.sourceforge.net/jasperreports/components" xsi: schemaLocation = "http://jasperreports.sourceforge.net/jasperreports/components http: //jasperreports.sourceforge Purge / xsd / components.xsd "textPosition =" bottom "& gt; & Lt; Jr: codeExpression & gt; & Lt; [CDATA [$ F {number}]] & gt; & Lt; / Jr: codeExpression & gt; & Lt; / Jr: Code 128 & gt; & Lt; / componentElement & gt; "Text" itemprop = "text"> Create a style after this, it is called "barcode", like: & lt; Style name = "barcode" fontName = "Helvetica" fONTSIZE = "10" hAlign = "center" valign = "center" /> and set the property of your barcode element to "barcode".
Read more

django - CommandError: You must set settings.ALLOWED_HOSTS if DEBUG is False -

I use Django 1.6.5 with settings in my program txsite: DEBUG = true I set the lie to debug, but when I get the runner , I get the following error: CommandError: You have to set the settings. OLOWOWHESTS If DEBUG is False I ALLOWED_HOSTS = ['127.0.0.1', 'localhost'] but I get the same error. Does anyone know this address? Try ALLOWED_HOSTS = ['*'] Less secure If you are not on a firewall or public LAN, but what I use and it works. Edit: Interestingly enough, I have to add some of my 1.8 projects, even if DEBUG = True . Why so very uncertain
Read more