opengl - What's glUniformBlockBinding used for? -


Assume that I have a shader program with the uniform block at index 0 .

To compel the uniformbuffer, there is enough enough to bind the uniformbuffer in the following block: 

  glUseprogram (program); Glubbind Buffer (GL_UNIFORM_BUFFER, buffer); Glibindbuffarbase (GL_UIIFRMBUFFER, 0, buffer);   
 I only have to use  glUniformBlockBinding  when I bind buffer to a different index in the shader program.  
  // ... glBindBufferBase (GL_UNIFORM_BUFFER, 1, buffer) glUniformBlockBinding (program, 0, 1); // Uniform Block 1 index 0   
 Did I understand it correctly? If I use buffer in different programs where appropriate blocks have different indices, then do I have to use  glUniformBlockBinding ?   
 
 
 Active program block indices per program are different from global binding locations.  
 The general idea here is that you consider using the proper layout, you can bind the uniform buffer, one place in GL and use it in many GLSL programs. But mapping between individual buffer block index and global binding points of GL of each program needs to be established by this command.  
 To keep it in perspective, consider sample uniforms.  
 Uniform space is similar to any other uniform, but this location does not actually say anything about the Texture Image Unit which uses the sample. For example, you can still tie your texture in  GL_TEXTURE7  instead of the location of the sample uniform.  
 The only conceptual difference between samples and uniform buffers in this regard is that you do not assign that the binding space using  glUniform1i (...)  to set the index .  
 
 With GLSL 4.20 (and applied retroactively), you can clearly establish the binding space of a specific block from within the shaders.  
 GLSL 4.20  (or the appropriate extension)  allows you to type the following:  
  Layout (std140, binding = 0) Uniform MyUniform Block { vec4 foo; vec4 times; };   
 In this way, you do not need to set an identical block index for   MyUiniformBlock   any time; This block will be bound to  0  at link-time.

Comments

Post a Comment

Popular posts from this blog

Verilog Error: output or inout port "Q" must be connected to a structural net expression -

I get the error every time, I try to compile. I'm not sure why anyone can help is? I'm new to verilog. Module D_FF (clerk, d, reset_n, q); Input D, Clack, reset_en; Output Q; reg Q; lab4_gdl f1 (.lk (~ clk), d (d), .q.m (qm)); lab4_GDL f2 (.Clk (Clk), D (QM), .Q (Q)); Always start at @ (posedge clk, neggeous reset_n) (Reset_n == 0) Q & lt; = 0; Other questions & lt; = D; Edit End: The problem is what we are asking to do: In this section, you apply the memory / registration circuit on the AlterEdie 2 board. will do. The circuit has the following specifications: The present value of swift SW15-0 on the D2 board should be shown in four hexadecimal four sections of HEX3-0. This part of the circuit will be combination logic. To use an active-less asynchronous reset and KEY1 to use KEY0 as the clock input, you must store SW15-0in in a 16-bit register in the value The register should be enabled to have a 16-bit positive edge, which uses the embedded D flip-flo
Read more

jasper reports - How to center align barcode using jasperreports and barcode4j -

I use iReport 5.5.0 . How to align a barcode component to the center The relevant piece of my jrxml is below & Lt; JR: Code 128 xmlns: JR = "http://jasperreports.sourceforge.net/jasperreports/components" xsi: schemaLocation = "http://jasperreports.sourceforge.net/jasperreports/components http: //jasperreports.sourceforge Purge / xsd / components.xsd "textPosition =" bottom "& gt; & Lt; Jr: codeExpression & gt; & Lt; [CDATA [$ F {number}]] & gt; & Lt; / Jr: codeExpression & gt; & Lt; / Jr: Code 128 & gt; & Lt; / componentElement & gt; "Text" itemprop = "text"> Create a style after this, it is called "barcode", like: & lt; Style name = "barcode" fontName = "Helvetica" fONTSIZE = "10" hAlign = "center" valign = "center" /> and set the property of your barcode element to "barcode".
Read more

c# - ASP.NET MVC - Attaching an entity of type 'MODELNAME' failed because another entity of the same type already has the same primary key value -

In brief, the wrapper module is inserted during posting and the status of an entry is changed to 'modified' . Before changing the state, the state is set to 'separate', but calling attachments () causes the same error to be thrown away. I am using EF 6. Model / wrapper class public class avi model {public A is a {get; Set; } Public listing & lt; B & gt; B {received; Set; } Public cc {receipt; Set; }} Administrator edit public functioning (int? id) {if (id == null) {new HttpStatusCodeResult (HttpStatusCode.BadRequest); } If (! Conveyor Access (id.Value)) new HTTPTitus code result (HTTP status code. Forbidden); Var aViewModel = new AViewModel (); aViewModel.A = db.As.Find (id); If (aViewModel.Receipt == zero) {return HttpNotFound (); } aViewModel.b = db.Bs.Where (x => x.aid == id.Value) .Oolist (); AViewModel.Vendor = db.Cs.Where (x => x.cid == aViewModel.a.cID) .FirstOrDefault (); See Return (aViewModel); } [HTPFost] [Valid AntitiferousTeacon
Read more