python - What is causing this TypeError? -


I have two separate files, which have two separate classes (let them be replaced by Foo And times ). In the file ( Foo.py )

class Foo , I have: 

  square fu: def __init __ (auto): ...   
 and  bar  in the file ( Bar.py )>, with me Foo class bar (Foo.Foo): def __init __ (self): ...   
 when I send my code to:  To run, I get this  TypeError :  
  traceback (most recent call final): File "Bar.py", line 2,   
 It's telling me to pass There are 4 arguments for  __init __  when code is the only argument, then  self    
 
 
 It seems to me that your problem is that you are importing the class directly, but then trying to access it through the module name.  
 If you have a module source file  foo.py  inside a class  Foo  then you can use it like this:  < You can also:  
   
  
 Pre>  but you are trying to do this:   
 code>, first  foo  is your class. .  parses  foo  after python and looks for a class member called  Foo .  
 Note: I suggest you follow the PEP 8 guidelines, and your module should use the following-case names. Thus  foo.py  instead of  foo.py .

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