int - How to sort the digits of a number and get another number in Python? -


Beginning on Python and trying to code this program: 

  a = 0 number = int (Input ("Choose four digit numbers:"), while the number! = 6174: #Captrecor continuously sorted (number) sorted (number, reverse = true) big = "" .joined (sorted (number, reverse = true)) small = "" (Sorted) number = (int) - int (small)) a + = 1 print (a + "repeated.")   
 I get the following error :  
  sorted (number) typeError: 'int' object is not iterable   
 Then how do I get the  number  and the second number Do you?   
 
 
 First of all,  sorted  around a nearby Not only does not change, you need to do something like  a = sorted (a) .  
 Now for your example, both of you are trying to work with  number  as  int  and a  str < / code>. You need to convert between  str  and  int  when necessary: ​​ 
  a = 0 number = input ("four digit number Select: ") number = =" 6174 ": large =" ".joined (sorted (number, reverse = true)) small =" ".join (sorted (number)) number = str (int ( Big) - int (short end,  a  a  int , so you can 'do not  int + str  in the previous print statement Either  print (str (ara) + "iterations") or <+ code>. < / P>

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