python - Multiple workers consume same message from RabbitMQ queue -


I use the py-amqp module and Python 3.4 when I run more than 1 listener and message to a constructor The listener starts to publish the message and to start this process simultaniously I do not need that kind of behavior because the messages should be written only once in DB. Therefore, the fastest employees write messages to DB and all other workers say that the message already exists.

Producer: 

  Import Import import from import from json import import randomly. Import settings RMQ_PASSWORD, RMQ_USER, RMQ_HOST, RMQ_EXCHANGE def main (): conn = amqp.Connection (RMQ_HOST, RMQ_USER, RMQ_PASSWORD, SSL = False) ch = conn.channel () ch.exchange_declare (RMQ_EXCHANGE, 'fanout') req = {"Request": {"transaction_number": random.randint (100000, 9999999999)}} message = json.dumps (req) msg ​​= amqp.message (message) ch.basic_publish (msg, RMQ_EXCHANGE) ch.close ( ) conn.close () if __name__ == '__main__': in range (100) for x: main ()   
 worker: From the pipeline import pipeline to fun control import, lent settings Import DB_CONNECTION_STRING, RMQ_EXCHANGE, RMQ_HOST, RMQ_PASSWORD, RMQ_USER import amqp DB = dal.DAL (DB_CONNECTION_STRING) message_processor = Pipeline.pplline (db) def callback (channel, msg): channel.basic_ack (msg.delivery_tag) message_processor.process msg) if msg.body == 'left': channel.basic_cancel (msg.consumer_tag) def main () : Conn = amqp.Connection (RMQ_HOST, RMQ_USER, RMQ_PASSWORD, SSL = False) ch = conn.channel () ch Exchange _ Dislayer (RMQXNNNTNAGN, FANAPANG) qname, _, _ = ch.queue_declare () ch.queue_bind (qname, rmq_EXCHANGE ch.basic_consume (qname, callback = partial (callback, ca), while ch.callbacks: ch.wait ()   
 also:  
  User @ rbitmq: ~ $ pseudo rabbitemcontell list_band Listings Binding ... Exchange AMKJen - CRTGFSLE6GWLLRV7PPUQEMMAG- CRTJFSLU6GLLVW7PQ [] ExchangeMcGen-1X3WVGF5OKN_GCNFPJKFG QIMMJen-1X3VVGF5OKN_GCNFPJKFG [] ... exchange amq.gen-yf8ieG1AK9x83Vz4GBj-ZA qi amq.gen-yf8ieG1AK9x83Vz4GBj-ZA [] Exchange AntiSpy.test line entryEttest [] Antipee Exchange Ent Piktest queue [] Ajhjhe exchange Amakkjen - Siartijefseli 6 Jivielelarwu 7 pp Q [] Ajhjhe Exchange Exchange .gen-1X3vwGF5OKn_gcnofpJKFg line [] ... Azaza exchange amq.gen-yf8ieG1AK9x83Vz4GBj-ZA Queue [] Azza exchange entryapi.test queue [] ... done.    
 
 
 I think you use the wrong type set up for your use case are doing. You have a publisher published in one currency and you want to read the messages and want to write them in DB. You want to write DB with many consumers doing this so that you can increase the throughput. Fanout will result in a lot of queue for repeating the exchange message and the dubbing of DB to many consumers of the same data. You need to use the 'work queue' Each exchange will exchange a default (no type, or direct exchange with all messages using the same routing key). All messages sent to the exchange will be sent in a single quote.           html>

Comments

Post a Comment

Popular posts from this blog

Verilog Error: output or inout port "Q" must be connected to a structural net expression -

I get the error every time, I try to compile. I'm not sure why anyone can help is? I'm new to verilog. Module D_FF (clerk, d, reset_n, q); Input D, Clack, reset_en; Output Q; reg Q; lab4_gdl f1 (.lk (~ clk), d (d), .q.m (qm)); lab4_GDL f2 (.Clk (Clk), D (QM), .Q (Q)); Always start at @ (posedge clk, neggeous reset_n) (Reset_n == 0) Q & lt; = 0; Other questions & lt; = D; Edit End: The problem is what we are asking to do: In this section, you apply the memory / registration circuit on the AlterEdie 2 board. will do. The circuit has the following specifications: The present value of swift SW15-0 on the D2 board should be shown in four hexadecimal four sections of HEX3-0. This part of the circuit will be combination logic. To use an active-less asynchronous reset and KEY1 to use KEY0 as the clock input, you must store SW15-0in in a 16-bit register in the value The register should be enabled to have a 16-bit positive edge, which uses the embedded D flip-flo
Read more

jasper reports - How to center align barcode using jasperreports and barcode4j -

I use iReport 5.5.0 . How to align a barcode component to the center The relevant piece of my jrxml is below & Lt; JR: Code 128 xmlns: JR = "http://jasperreports.sourceforge.net/jasperreports/components" xsi: schemaLocation = "http://jasperreports.sourceforge.net/jasperreports/components http: //jasperreports.sourceforge Purge / xsd / components.xsd "textPosition =" bottom "& gt; & Lt; Jr: codeExpression & gt; & Lt; [CDATA [$ F {number}]] & gt; & Lt; / Jr: codeExpression & gt; & Lt; / Jr: Code 128 & gt; & Lt; / componentElement & gt; "Text" itemprop = "text"> Create a style after this, it is called "barcode", like: & lt; Style name = "barcode" fontName = "Helvetica" fONTSIZE = "10" hAlign = "center" valign = "center" /> and set the property of your barcode element to "barcode".
Read more

c# - ASP.NET MVC - Attaching an entity of type 'MODELNAME' failed because another entity of the same type already has the same primary key value -

In brief, the wrapper module is inserted during posting and the status of an entry is changed to 'modified' . Before changing the state, the state is set to 'separate', but calling attachments () causes the same error to be thrown away. I am using EF 6. Model / wrapper class public class avi model {public A is a {get; Set; } Public listing & lt; B & gt; B {received; Set; } Public cc {receipt; Set; }} Administrator edit public functioning (int? id) {if (id == null) {new HttpStatusCodeResult (HttpStatusCode.BadRequest); } If (! Conveyor Access (id.Value)) new HTTPTitus code result (HTTP status code. Forbidden); Var aViewModel = new AViewModel (); aViewModel.A = db.As.Find (id); If (aViewModel.Receipt == zero) {return HttpNotFound (); } aViewModel.b = db.Bs.Where (x => x.aid == id.Value) .Oolist (); AViewModel.Vendor = db.Cs.Where (x => x.cid == aViewModel.a.cID) .FirstOrDefault (); See Return (aViewModel); } [HTPFost] [Valid AntitiferousTeacon
Read more