python - BeautifulSoup: Search from leaf to root to get the "deepest" elements first? -


As for a research project, I want to remove all the "documentation units" of a document unit in Python documentation

  • A class (DL class: class)
  • A (DL class: method)
  • section (div squares: section) < P> And as you can guess, they should be nested in such a manner: There are many classes in a section, which have many methods but in reality it is very irregular Is. Example 1: If there are many classes and methods in one section: I want to get each method alone and each class without methods (which I have already received) and Without the classes (which I already have in that case) and methods (which I already have), but with the rest (as there are too many additional things)

    Example2: If there is no method or no section in the class In which they appear, so I have described above them and do not forget them.

    Note: This is not easy, but I would like to get them all into a list which has the same command as the original documentation.

    I tried it with a beautiful soup but I think that for this purpose I have to find "deep root" from the leaf to get the deepest elements - which are beautiful ( afaik) is not supported by Sundasub 4.

    But in reality this is not the main problem.

    I appreciate your point

    It seems that it is not possible .

    So what I did to solve this problem has to be repeated elements (which I was using using .descendants) repeatedly and then I have replaced nested-elements with a placeholder So that the change could make visible (using replace_with).

    As before I used to have dynasties, nested elements are also stored.

    • Comments

    Post a Comment

    Popular posts from this blog

    c# - ASP.NET MVC - Attaching an entity of type 'MODELNAME' failed because another entity of the same type already has the same primary key value -

    In brief, the wrapper module is inserted during posting and the status of an entry is changed to 'modified' . Before changing the state, the state is set to 'separate', but calling attachments () causes the same error to be thrown away. I am using EF 6. Model / wrapper class public class avi model {public A is a {get; Set; } Public listing & lt; B & gt; B {received; Set; } Public cc {receipt; Set; }} Administrator edit public functioning (int? id) {if (id == null) {new HttpStatusCodeResult (HttpStatusCode.BadRequest); } If (! Conveyor Access (id.Value)) new HTTPTitus code result (HTTP status code. Forbidden); Var aViewModel = new AViewModel (); aViewModel.A = db.As.Find (id); If (aViewModel.Receipt == zero) {return HttpNotFound (); } aViewModel.b = db.Bs.Where (x => x.aid == id.Value) .Oolist (); AViewModel.Vendor = db.Cs.Where (x => x.cid == aViewModel.a.cID) .FirstOrDefault (); See Return (aViewModel); } [HTPFost] [Valid AntitiferousTeacon...
    Read more

    jasper reports - How to center align barcode using jasperreports and barcode4j -

    I use iReport 5.5.0 . How to align a barcode component to the center The relevant piece of my jrxml is below & Lt; JR: Code 128 xmlns: JR = "http://jasperreports.sourceforge.net/jasperreports/components" xsi: schemaLocation = "http://jasperreports.sourceforge.net/jasperreports/components http: //jasperreports.sourceforge Purge / xsd / components.xsd "textPosition =" bottom "& gt; & Lt; Jr: codeExpression & gt; & Lt; [CDATA [$ F {number}]] & gt; & Lt; / Jr: codeExpression & gt; & Lt; / Jr: Code 128 & gt; & Lt; / componentElement & gt; "Text" itemprop = "text"> Create a style after this, it is called "barcode", like: & lt; Style name = "barcode" fontName = "Helvetica" fONTSIZE = "10" hAlign = "center" valign = "center" /> and set the property of your barcode element to "barcode".
    Read more

    django - CommandError: You must set settings.ALLOWED_HOSTS if DEBUG is False -

    I use Django 1.6.5 with settings in my program txsite: DEBUG = true I set the lie to debug, but when I get the runner , I get the following error: CommandError: You have to set the settings. OLOWOWHESTS If DEBUG is False I ALLOWED_HOSTS = ['127.0.0.1', 'localhost'] but I get the same error. Does anyone know this address? Try ALLOWED_HOSTS = ['*'] Less secure If you are not on a firewall or public LAN, but what I use and it works. Edit: Interestingly enough, I have to add some of my 1.8 projects, even if DEBUG = True . Why so very uncertain
    Read more