JavaScript closure and scope chain -

Can anyone explain why document.write part always 10 output?

  function creatFunctions () {var results = new array (); For (var i = 0; i & lt; 10; i ++) {result [i] = function () {return i; }} Return result; } Var funcs = creatFunctions (); For (var i = 0; i & lt; funcs.length; i ++) {document.write (funcs [i] () + "
  
 I think the answer to this question is more intense than the duplicate question , so this post is worth keeping.   
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 Sure.  
 In your  in the  loop, you reference  i . Do you expect this to happen that every stop time ceremony has been created but I get a snapshot, so in the first ceremony it will return 0, then 1, etc.  
 What is actually happening is that external variables each closure  i  is to get references, which  i  to  i  in the loop as .  
 So, for the first time through the loop, you get a task that gives  i , which is 0 at this point. Next time you get two functions which are  i , which is now 1, etc.  
 In the loop at the end,  i == 10 , and each function  i , so they all return 10  
  Update address address question.   
 It's a little confusing since you use  i  in two different contexts. I could make a very slight changes in your code will, so that it becomes clear that what is happening:  
  function creatFunctions () {var result = new Array (); For (var i = 0; i & lt; 10; i ++) {result [i] = function () {return i; }} Return result; } Var funcs = creatFunctions (); // Note: I it`s the `unrelated_variable` for I`d change (unrelated_variable = 0 var; unrelated_variable & LT; funcs.length; unrelated_variable ++) {document.write (funcs [unrelated_variable] () + '& lt ;);}   
 ... You can return all the functions in your  creatFunctions ()  function  i < / code>. in particular, they say that you return  I  to create the loop.  
 other variables, which I  unrelated_variable  has been named, there is no effect on the price derived from your closing.  
  Results [i] = F Quote () {return i;}   
 ...  is not similar to the result [2] = 2 . This means the  result [2] = the_current_value_of_i