mysql - Inserting data to db in PHP -


I am trying to insert somethig to db and after getting this code I get a blank page in php . Cam you help me? If I free up all the pages then I get an empty page, like now I get the Imprint Container

   Query // ('INSERT IN' idoctor_db`. User '(`id`,` log in`, `password`,` name`, `level`] // value (' 5 ',' cave5 ',' rui ' 5 ',' Kevekeve 5 ',' 3 '); //'); }}? & Gt; & Lt ;! DOCTYPE html & gt; & Lt; Html & gt; & Lt; Top & gt; & Lt; Title & gt; Login & lt; / Title & gt; & Lt; link rel = "stylesheet" href = "css / login.css" /> & Lt; / Head & gt; & Lt; Body & gt; & Lt; Div class = "container" & gt; & Lt; form action = "& lt ;? php create () ;? & gt;" Method = "post" & gt; & Lt; Input type = "text" name = "username" placeholder = "user name ..." /> & Lt; Input type = "password" name = "password" placeholder = "password" /> & Lt; Input type = "password" name = "password_conf" placeholder = "confirm password" / & gt; & Lt; Input type = "text" name = "nick" placeholder = "nick" /> & Lt; Input type = "submit" value = "create" name = "submit" /> & Lt; / Form & gt; & Lt; / Div & gt; & Lt; / Body & gt; & Lt; / Html & gt;  

If there is no error in running this query, you will see an empty page Will give

To ensure that all the work is done in the background, check out your mysql table to see if the inclusion works.

If you want to check the outcome of the query ... just do the following

  $ result = $ db- & gt; Query ('INSERT IN' idoctor_db`. User '(`id`,` log in`, `password`,` name`, `level`] value (' 4 ',' kev4 ',' root ',' kevkev4 ',' 3 ');';); If ($ result) {echo 'success'; } Else {echo 'unsuccessful'; }    

Comments

Popular posts from this blog

Verilog Error: output or inout port "Q" must be connected to a structural net expression -

jasper reports - How to center align barcode using jasperreports and barcode4j -

c# - ASP.NET MVC - Attaching an entity of type 'MODELNAME' failed because another entity of the same type already has the same primary key value -