c - Why does the cstdlib strncpy crash whilst copying a char array to a character pointer -


यह मेरा कोड है: 

  char * toc (char src [STRING_SIZE], char * Dest) {if (src [0] == 0) dest = NULL; अन्य strncpy (dest, & src [0], आकार_टी (strlen (src))); }   
 
 इसे कैसे बुलाया जाता है:  
  typedef struct sdata {char * point_one; } tsdata tsdata sdata; चार नाम [STRING_SIZE] = "point_data"; TOC (नाम, sdata.point_one);   
 strncpy हमेशा क्रैश करता है  
 मैं क्या कर रहा हूँ गलत?   
 
 
 यह कोड:  
  typedef struct sdata {char * point_one; } tsdata tsdata sdata; चार नाम [STRING_SIZE] = "point_data"; TOC (नाम, sdata.point_one);   
 कॉल  Toc  दूसरे तर्क के साथ एक अनिर्धारित संकेतक, जो कि मूल्य से पारित होता है।  
 उस  अनिश्चित मूल्य   
 
 सामान्य टिप्पणियां।  
 
 इस फ़ंक्शन घोषणा में ,  <पूर्व>  शून्य TOC (char src [STRING_SIZE], char * dest)   
     
  •   STRING_SIZE  द्वारा उपेक्षित है संकलक और निम्न कोड के लिए उपलब्ध नहीं है।   
     
     और इस कोड स्निपेट में:  
      if (src [0] == 0) dest = NULL;   
       
    •  असाइनमेंट एक स्थानीय चर (एक फ़ंक्शन तर्क) का मान बदलता है, जिसका उपयोग फ़ंक्शन में नहीं किया जाता है।   
       < p> इसके अलावा, अपडेट किए गए प्रश्न के लिए जहां फ़ंक्शन घोषणा को  
        char * ToC (char src [STRING_SIZE], char * dest) में बदल दिया गया था   
         
      •  फ़ंक्शन में  return  कथन नहीं है, इसलिए फ़ंक्शन परिणाम का कोई भी उपयोग अपरिभाषित व्यवहार है।

Comments

Post a Comment

Popular posts from this blog

c# - ASP.NET MVC - Attaching an entity of type 'MODELNAME' failed because another entity of the same type already has the same primary key value -

In brief, the wrapper module is inserted during posting and the status of an entry is changed to 'modified' . Before changing the state, the state is set to 'separate', but calling attachments () causes the same error to be thrown away. I am using EF 6. Model / wrapper class public class avi model {public A is a {get; Set; } Public listing & lt; B & gt; B {received; Set; } Public cc {receipt; Set; }} Administrator edit public functioning (int? id) {if (id == null) {new HttpStatusCodeResult (HttpStatusCode.BadRequest); } If (! Conveyor Access (id.Value)) new HTTPTitus code result (HTTP status code. Forbidden); Var aViewModel = new AViewModel (); aViewModel.A = db.As.Find (id); If (aViewModel.Receipt == zero) {return HttpNotFound (); } aViewModel.b = db.Bs.Where (x => x.aid == id.Value) .Oolist (); AViewModel.Vendor = db.Cs.Where (x => x.cid == aViewModel.a.cID) .FirstOrDefault (); See Return (aViewModel); } [HTPFost] [Valid AntitiferousTeacon...
Read more

jasper reports - How to center align barcode using jasperreports and barcode4j -

I use iReport 5.5.0 . How to align a barcode component to the center The relevant piece of my jrxml is below & Lt; JR: Code 128 xmlns: JR = "http://jasperreports.sourceforge.net/jasperreports/components" xsi: schemaLocation = "http://jasperreports.sourceforge.net/jasperreports/components http: //jasperreports.sourceforge Purge / xsd / components.xsd "textPosition =" bottom "& gt; & Lt; Jr: codeExpression & gt; & Lt; [CDATA [$ F {number}]] & gt; & Lt; / Jr: codeExpression & gt; & Lt; / Jr: Code 128 & gt; & Lt; / componentElement & gt; "Text" itemprop = "text"> Create a style after this, it is called "barcode", like: & lt; Style name = "barcode" fontName = "Helvetica" fONTSIZE = "10" hAlign = "center" valign = "center" /> and set the property of your barcode element to "barcode".
Read more

django - CommandError: You must set settings.ALLOWED_HOSTS if DEBUG is False -

I use Django 1.6.5 with settings in my program txsite: DEBUG = true I set the lie to debug, but when I get the runner , I get the following error: CommandError: You have to set the settings. OLOWOWHESTS If DEBUG is False I ALLOWED_HOSTS = ['127.0.0.1', 'localhost'] but I get the same error. Does anyone know this address? Try ALLOWED_HOSTS = ['*'] Less secure If you are not on a firewall or public LAN, but what I use and it works. Edit: Interestingly enough, I have to add some of my 1.8 projects, even if DEBUG = True . Why so very uncertain
Read more