sar - Assembly sarl and idivl - interpreting -


I have a problem understanding the following assembly code. It would be great if you can give me an example with numbers That's how it looks behind the scenes. 

  movl $ 0,% ecx movl $ 0,% ex addl $ 1,% ex movl% eax,% $ 31,% edx idivl $ 7 movl% edx,% eax movl (% Esp,% eax, 4),% eax movl% eax, (% esp,% ecx, 4)   
 I think that I can not interpret serial and move because My result does not make sense ..  
 Thank you very much for your help !! I am sitting in front of that code for 3 hours; ^^  
 I think:  
 ecx = 0  
 eax = 0  
 eax = 0 + 1 = 1  
 edx = eax = 1  
 now ADX Transfer = & gt; Adx = 0  
 Now edx: eax is divided by 7?  
 Why can not I just set up AdX = 0 and leave Ciral? Will not this happen?   
 
 
 
 I just  edx  = 0 and leave  sarl  outside? Will not it be like this?   
 Not for a signed partition, which is  ivive  are following two instructions that  CDQ  does the instructions:    movl% eax,% edx sarl $ 31,% edx   
 is it,  
 " sar  operated is positive and operator is negative if the setting of empty bits keeps the signal of Source Operation clear by clearing the empty bit posts. " 
 and  
 
 " CDQ  dictates a double-value mark in the  EAX  register in each bit position (bit 31) The  CDQ  command can be used to create a quadruped dividend from a double before the double division. "   / Blockquote> 
 Note that  sarl  updates some status flag while the  cdq  does not, this New is  movl  +  sarl  as that would not be the same  cdq . It is not clear from the question why the code does not use only  cdq .

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