java - how to fix an error when calling a method? -


I must call the method that takes an array of parameters and moves the minimum value in front of the list. I am getting this line an error: 

  System.out.printf ("display number \ n", myList.minInteger);   
 Here's the code:  
  import java.util. *; Public square MinToFront {public static zero main (string [] args) {MinToFront myList = new MinToFront (); ArrayList & LT; Integer & gt; List = New Arrestist & lt; Integer & gt; (); List.add (3); List.add (8); List.add (92); List.add (4); List.add (2); List.add (17); List.add (9); myList.minToFront (list); System.out.printf ("Display Number \ n", myList.minInteger); } // The main public static zero minToFront (ArrayList & lt; integer & gt; minInteger) end {int result = 0; int min = minInteger.get (0); (Int (= minInteger.get (i) & lt; min) {min = minInteger.get (i); Results = minute; }} MinInteger.add (0, minInteger.remove (result));} // method end // class    
 
 main ()  .  
 Finally, you should put the parentheses at the end of a method while calling it.  
 This is your The code is correct:  
  public static zero minToFront (ArrayList & lt; integer & gt; minInteger) {int result = 0; int min = minInteger.get (0); (int i = 0; For i & lt; minInteger.size (); i ++) (if (minInteger.get (i) & lt; min) {min = minInteger.get (i); Results = minute;}} minInteger .add (0, result); minInteger.remove (result);} // end of method // // end of class

Comments

Post a Comment

Popular posts from this blog

c# - ASP.NET MVC - Attaching an entity of type 'MODELNAME' failed because another entity of the same type already has the same primary key value -

In brief, the wrapper module is inserted during posting and the status of an entry is changed to 'modified' . Before changing the state, the state is set to 'separate', but calling attachments () causes the same error to be thrown away. I am using EF 6. Model / wrapper class public class avi model {public A is a {get; Set; } Public listing & lt; B & gt; B {received; Set; } Public cc {receipt; Set; }} Administrator edit public functioning (int? id) {if (id == null) {new HttpStatusCodeResult (HttpStatusCode.BadRequest); } If (! Conveyor Access (id.Value)) new HTTPTitus code result (HTTP status code. Forbidden); Var aViewModel = new AViewModel (); aViewModel.A = db.As.Find (id); If (aViewModel.Receipt == zero) {return HttpNotFound (); } aViewModel.b = db.Bs.Where (x => x.aid == id.Value) .Oolist (); AViewModel.Vendor = db.Cs.Where (x => x.cid == aViewModel.a.cID) .FirstOrDefault (); See Return (aViewModel); } [HTPFost] [Valid AntitiferousTeacon...
Read more

jasper reports - How to center align barcode using jasperreports and barcode4j -

I use iReport 5.5.0 . How to align a barcode component to the center The relevant piece of my jrxml is below & Lt; JR: Code 128 xmlns: JR = "http://jasperreports.sourceforge.net/jasperreports/components" xsi: schemaLocation = "http://jasperreports.sourceforge.net/jasperreports/components http: //jasperreports.sourceforge Purge / xsd / components.xsd "textPosition =" bottom "& gt; & Lt; Jr: codeExpression & gt; & Lt; [CDATA [$ F {number}]] & gt; & Lt; / Jr: codeExpression & gt; & Lt; / Jr: Code 128 & gt; & Lt; / componentElement & gt; "Text" itemprop = "text"> Create a style after this, it is called "barcode", like: & lt; Style name = "barcode" fontName = "Helvetica" fONTSIZE = "10" hAlign = "center" valign = "center" /> and set the property of your barcode element to "barcode".
Read more

django - CommandError: You must set settings.ALLOWED_HOSTS if DEBUG is False -

I use Django 1.6.5 with settings in my program txsite: DEBUG = true I set the lie to debug, but when I get the runner , I get the following error: CommandError: You have to set the settings. OLOWOWHESTS If DEBUG is False I ALLOWED_HOSTS = ['127.0.0.1', 'localhost'] but I get the same error. Does anyone know this address? Try ALLOWED_HOSTS = ['*'] Less secure If you are not on a firewall or public LAN, but what I use and it works. Edit: Interestingly enough, I have to add some of my 1.8 projects, even if DEBUG = True . Why so very uncertain
Read more