php foreach loop insert into two tables -


I want to insert the table into the table.

Each name can have several addresses.

name will be in table1 and all addresses will be related to another table2 in name

My array is below: 

  array ([name] => array ([0] = & gt; Jack [1] => Jill [ 2] = array ([0] = & gt; array ([0] = & gt; Jack_Address1 [1] => Jack_Address2 [2] => Jack_Edress 3) [1] => array ([0] = & gt; jill_address1 [1] = & gt; jill_address2 [2] => jill_address3) [2] = & gt; array ([0] => tom_address1 [1] = & gt; tom_address2 [2] => Below is the one that I tried:  
  foreach ($ _ request ['room_name'] as the $ key => $ value) {mysql_query ("table1 (not ) Enter values ​​in the values ​​($ value) "$ insert_id = mysql_insert_id (); foreach ($ _ request ['address'] $ key1 = & gt; $ value1) {mysql_query (" Insert ID, Address in Table 2 ") value $ insert_id, $ value1) ");}}    
 
 
 Drilling is not it should be:  
  foreach ($ _ request ['name'] $ key = & gt; $ value) {$ value = mysql_real_escape_string ($ value); Mysql_query ("Enter in Table 1 (Name) values ​​('$ value')"); Foreign Currency ($ _ request ['address'] [$ key] $ key1 => $ value1) {$ value1 = mysql_real_escape_string ($ value1); Mysql_query ("Enter in Table 2 (id, address) values ​​(LAST_INSERT_ID (), '$ value1');); }}

Comments

Post a Comment

Popular posts from this blog

c# - ASP.NET MVC - Attaching an entity of type 'MODELNAME' failed because another entity of the same type already has the same primary key value -

In brief, the wrapper module is inserted during posting and the status of an entry is changed to 'modified' . Before changing the state, the state is set to 'separate', but calling attachments () causes the same error to be thrown away. I am using EF 6. Model / wrapper class public class avi model {public A is a {get; Set; } Public listing & lt; B & gt; B {received; Set; } Public cc {receipt; Set; }} Administrator edit public functioning (int? id) {if (id == null) {new HttpStatusCodeResult (HttpStatusCode.BadRequest); } If (! Conveyor Access (id.Value)) new HTTPTitus code result (HTTP status code. Forbidden); Var aViewModel = new AViewModel (); aViewModel.A = db.As.Find (id); If (aViewModel.Receipt == zero) {return HttpNotFound (); } aViewModel.b = db.Bs.Where (x => x.aid == id.Value) .Oolist (); AViewModel.Vendor = db.Cs.Where (x => x.cid == aViewModel.a.cID) .FirstOrDefault (); See Return (aViewModel); } [HTPFost] [Valid AntitiferousTeacon...
Read more

jasper reports - How to center align barcode using jasperreports and barcode4j -

I use iReport 5.5.0 . How to align a barcode component to the center The relevant piece of my jrxml is below & Lt; JR: Code 128 xmlns: JR = "http://jasperreports.sourceforge.net/jasperreports/components" xsi: schemaLocation = "http://jasperreports.sourceforge.net/jasperreports/components http: //jasperreports.sourceforge Purge / xsd / components.xsd "textPosition =" bottom "& gt; & Lt; Jr: codeExpression & gt; & Lt; [CDATA [$ F {number}]] & gt; & Lt; / Jr: codeExpression & gt; & Lt; / Jr: Code 128 & gt; & Lt; / componentElement & gt; "Text" itemprop = "text"> Create a style after this, it is called "barcode", like: & lt; Style name = "barcode" fontName = "Helvetica" fONTSIZE = "10" hAlign = "center" valign = "center" /> and set the property of your barcode element to "barcode".
Read more

django - CommandError: You must set settings.ALLOWED_HOSTS if DEBUG is False -

I use Django 1.6.5 with settings in my program txsite: DEBUG = true I set the lie to debug, but when I get the runner , I get the following error: CommandError: You have to set the settings. OLOWOWHESTS If DEBUG is False I ALLOWED_HOSTS = ['127.0.0.1', 'localhost'] but I get the same error. Does anyone know this address? Try ALLOWED_HOSTS = ['*'] Less secure If you are not on a firewall or public LAN, but what I use and it works. Edit: Interestingly enough, I have to add some of my 1.8 projects, even if DEBUG = True . Why so very uncertain
Read more