why when I enter zeroes on the left of an integer , c++ borland compiler changes the integer value? -


इस सवाल का पहले से ही एक उत्तर है: < / p>

  • 7 जवाब

    यह कोड, जब मैं चलाऊँगा यह C ++ Borland संकलक 5.02 पर 

      # शामिल & lt; iostream.h & gt; शून्य मुख्य () {int x; CIN & gt; & gt; x; Cout & lt; & lt; एक्स; }   
     जब  0010  से  x  दर्ज करते हैं, तो आउटपुट है  8 ? और ये कुछ प्रविष्टियों के लिए जो इसके शून्य पर शून्य हैं, लेकिन सभी नहीं?   
     
     
     सी ++ में:  
       
    •  अस्थिर संख्या में एक अग्रणी  0  है।  
    •  हेक्साडेसिमल संख्या में एक अग्रणी  0x  है।  
    •  अन्यथा, आपके पास दशमलव संख्या है।   
       इसलिए:  
         
      •   0x10  एक हेक्साडेसिमल नंबर 16 है।  
      •   010  8 का प्रतिनिधित्व करने वाला एक ऑक्टल नंबर है।  
      •   10  10 अंकों का प्रतिनिधित्व करने वाला दशमलव संख्या है।

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