php - full path to upload files to server -


I am getting an error while uploading the file

I uploaded the file that uploads the file The problem is that I'm calling it with a different file and different folders, which means that my folder on which the image folder is changing. 

  WARNING: move_uploaded_file (http: // localhost)  
 (I have the folder name - "pictures / user files")  
  /dogger/images/usersFiles/13981072220-1.jpg) [function.move-uploaded-file]: failed to open the stream: HTTP wrapping in the \ "programming program (x86) \ wamp \ www \ dogger Does not support: 127: Warning: move_uploaded_file () [function.move-uploaded-file]: 'C: \ Program Files (x86) \ wamp \ tmp \ php9D89.tmp' to 'Unable to move to http: http : // func \ func.global.php: //localhost/dogger/images/usersFiles/13981072220-1.jpg 'In: \ Program I'm running a code from my local computer (x86) \ wamp \ www \ dogger \ func \ func.global.php on line 127   
:  
  if ($ _SERVER ['REMOTE_ADDR'] == "127.0.0.1") $ usersFiles = 'http: // local host / dogger / images / usersFiles /'; else $ usersFiles = '/ home / israelig / public_html / sites / dogger / pictures / usersfiles / '; $ [[File '] [' name '] [$ i]))   $ [' file '] [' tmp_name '] [$ i], $ usersfiles  
 
 
 The error message says,  move_uploaded_file  does not support writing HTTP you  Local file path , no URL.

Comments

Post a Comment

Popular posts from this blog

c# - ASP.NET MVC - Attaching an entity of type 'MODELNAME' failed because another entity of the same type already has the same primary key value -

In brief, the wrapper module is inserted during posting and the status of an entry is changed to 'modified' . Before changing the state, the state is set to 'separate', but calling attachments () causes the same error to be thrown away. I am using EF 6. Model / wrapper class public class avi model {public A is a {get; Set; } Public listing & lt; B & gt; B {received; Set; } Public cc {receipt; Set; }} Administrator edit public functioning (int? id) {if (id == null) {new HttpStatusCodeResult (HttpStatusCode.BadRequest); } If (! Conveyor Access (id.Value)) new HTTPTitus code result (HTTP status code. Forbidden); Var aViewModel = new AViewModel (); aViewModel.A = db.As.Find (id); If (aViewModel.Receipt == zero) {return HttpNotFound (); } aViewModel.b = db.Bs.Where (x => x.aid == id.Value) .Oolist (); AViewModel.Vendor = db.Cs.Where (x => x.cid == aViewModel.a.cID) .FirstOrDefault (); See Return (aViewModel); } [HTPFost] [Valid AntitiferousTeacon...
Read more

jasper reports - How to center align barcode using jasperreports and barcode4j -

I use iReport 5.5.0 . How to align a barcode component to the center The relevant piece of my jrxml is below & Lt; JR: Code 128 xmlns: JR = "http://jasperreports.sourceforge.net/jasperreports/components" xsi: schemaLocation = "http://jasperreports.sourceforge.net/jasperreports/components http: //jasperreports.sourceforge Purge / xsd / components.xsd "textPosition =" bottom "& gt; & Lt; Jr: codeExpression & gt; & Lt; [CDATA [$ F {number}]] & gt; & Lt; / Jr: codeExpression & gt; & Lt; / Jr: Code 128 & gt; & Lt; / componentElement & gt; "Text" itemprop = "text"> Create a style after this, it is called "barcode", like: & lt; Style name = "barcode" fontName = "Helvetica" fONTSIZE = "10" hAlign = "center" valign = "center" /> and set the property of your barcode element to "barcode".
Read more

django - CommandError: You must set settings.ALLOWED_HOSTS if DEBUG is False -

I use Django 1.6.5 with settings in my program txsite: DEBUG = true I set the lie to debug, but when I get the runner , I get the following error: CommandError: You have to set the settings. OLOWOWHESTS If DEBUG is False I ALLOWED_HOSTS = ['127.0.0.1', 'localhost'] but I get the same error. Does anyone know this address? Try ALLOWED_HOSTS = ['*'] Less secure If you are not on a firewall or public LAN, but what I use and it works. Edit: Interestingly enough, I have to add some of my 1.8 projects, even if DEBUG = True . Why so very uncertain
Read more