Javascript constructor behaviour -

I have a question regarding the JS constructor function. I have the following code:

  var PersonConstructorFunction = function (first name, last name, gender) {this.personFirstName = firstName; This.personListName = lastname; this.person gender = gender; this.personFullName = function () {return.personFirstName + "" + this.personListName; }; this.personGreeting = ceremony (person) {if (this.personGender == "male") {return "hello shri" + this.personFullName (); } And if (this.person gender == "female") {return "hello misses" + this.personFullName (); } And {return "Hello there!"; }}; }; var p = new public control functions ("Donald", "Duck", "Male"); P2 = new person control function ("Lola", "Bunny", "Women"); document.write (p2.personGreeting (p2) + "");   
 The result is very clear -  - Hello Mrs. Lola Bunny -   
 The question is: There are two equal objects and the properties and methods P2 with the same number when I call the person's greeting method and pass the second object as the argument, then I can not understand the following behavior:  
  ** document.write (p2.personGreeting (p) + ""); **   
 In this case, I receive  - Hello Mrs. Lola Bunny - , but what about the P object is passed in the form of logic?  
 The person gets the greeting of the person greeting, determines his gender, and the BSD shows the congratulations on the result.  
 Resally I learned C # and the constructors work there equally.   
 
 
 You are not doing anything with the passed parameters Since you are using  this , only the variables within your constructor are being called.  
 You can      person. PersonFullName ();  and this will mean that the parameter member will be called  personFullName ()  and not your constructor