algorithm - How to decide the sign of the permutation between two ordered set? -


Suppose A and B are two arrays of the same size and each without repetitive members. Is there any efficient algorithm that

1. decides that there are only one members in A and B

2. If the answer to 1 is true, then the determining the order of the conversion Which brings A

You can convert A in B by using an extent table Are: 

  pos = hash table (value -> position) b perm = [] for an A: if there is no position: return "not the same!" This part takes O (n) time required.  
 Now you have to get a signal of ordering.  
 You have at least two options:  
     
  •  It's definitely possible in O (n log n) or better  
  •  it's only linear It takes time   
     Actually you can use cycle decomposition directly on your input arrays, which will give a nice and small implementation.

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