c# - Determine a project's solution file location via Visual Studio Designer -


We have a statement that tries to determine where a particular folder is located, It's running locally (debug), or on a customer's machine (release), we see a different place for this. 

  #if (DEBUG) firefoxpat = @ ".. \ .. \ .. \ \ xulrunner \" is included; #else if (System.Diagnostics.Debugger.IsAttached) {firefoxPath = @ ".. .. .. .. .. .. \ XulRunner" is included; } Else {firefoxPath = Path.Combine (application.StartupPath, @ "XulRunner \"); } #endif   
 However, when we try to run a designer for one of the projects, this path is unable to resolve, because the working directory of the designer is: C: \ Program Files (x86) \ Microsoft Visual Studio 12.0 \ Common7 \ IDE If the folder's path is incorrect, the project will not run properly, and when the designer tries to load it, the designer crashes.  
 We can use it to determine that we are currently executing through the designer:  
  bool is InDesignMode = LicenseManager.UsageMode == LicenseWoodMod.Designment || System.Digagnostics.Debugger.IsAttached == is true;   
 My question is, how can we determine the path of solution through a designer, so that we can solve the path of that folder correctly, which we need?   
 
 
 You can get some assembly examples within the entire project, use the property and It can play with:  
  string assembly = new URI (assembly .gate assembly (typef (some kind of missing project)). Codebabes.AssolutePath; // At least you have bin \ debug Bin \ Release Now you can assume some conventions / and project directory You can find the string binDir = path.gate directoryname (binDir);   
 I do not know your exact case, but maybe  assembly.setting assembly ()  There may be enough and you do not need to load the entire assembly by giving one type.

Comments

Post a Comment

Popular posts from this blog

c# - ASP.NET MVC - Attaching an entity of type 'MODELNAME' failed because another entity of the same type already has the same primary key value -

In brief, the wrapper module is inserted during posting and the status of an entry is changed to 'modified' . Before changing the state, the state is set to 'separate', but calling attachments () causes the same error to be thrown away. I am using EF 6. Model / wrapper class public class avi model {public A is a {get; Set; } Public listing & lt; B & gt; B {received; Set; } Public cc {receipt; Set; }} Administrator edit public functioning (int? id) {if (id == null) {new HttpStatusCodeResult (HttpStatusCode.BadRequest); } If (! Conveyor Access (id.Value)) new HTTPTitus code result (HTTP status code. Forbidden); Var aViewModel = new AViewModel (); aViewModel.A = db.As.Find (id); If (aViewModel.Receipt == zero) {return HttpNotFound (); } aViewModel.b = db.Bs.Where (x => x.aid == id.Value) .Oolist (); AViewModel.Vendor = db.Cs.Where (x => x.cid == aViewModel.a.cID) .FirstOrDefault (); See Return (aViewModel); } [HTPFost] [Valid AntitiferousTeacon...
Read more

jasper reports - How to center align barcode using jasperreports and barcode4j -

I use iReport 5.5.0 . How to align a barcode component to the center The relevant piece of my jrxml is below & Lt; JR: Code 128 xmlns: JR = "http://jasperreports.sourceforge.net/jasperreports/components" xsi: schemaLocation = "http://jasperreports.sourceforge.net/jasperreports/components http: //jasperreports.sourceforge Purge / xsd / components.xsd "textPosition =" bottom "& gt; & Lt; Jr: codeExpression & gt; & Lt; [CDATA [$ F {number}]] & gt; & Lt; / Jr: codeExpression & gt; & Lt; / Jr: Code 128 & gt; & Lt; / componentElement & gt; "Text" itemprop = "text"> Create a style after this, it is called "barcode", like: & lt; Style name = "barcode" fontName = "Helvetica" fONTSIZE = "10" hAlign = "center" valign = "center" /> and set the property of your barcode element to "barcode".
Read more

django - CommandError: You must set settings.ALLOWED_HOSTS if DEBUG is False -

I use Django 1.6.5 with settings in my program txsite: DEBUG = true I set the lie to debug, but when I get the runner , I get the following error: CommandError: You have to set the settings. OLOWOWHESTS If DEBUG is False I ALLOWED_HOSTS = ['127.0.0.1', 'localhost'] but I get the same error. Does anyone know this address? Try ALLOWED_HOSTS = ['*'] Less secure If you are not on a firewall or public LAN, but what I use and it works. Edit: Interestingly enough, I have to add some of my 1.8 projects, even if DEBUG = True . Why so very uncertain
Read more