recursion - Java Recursive algorithm, I can't follow the logic -


So, the questions ask, what will be the output of this method when you pass it 3.

I plugged it into JCreator and received 010203010 and I have been completely confused. 

  Public static zero printX (int n) {if (n & lt; = 0) System.out.print (0); Other {printX (N-1); System.out.print (n); PrintX (n-2); }}   
 So this is my reason, it will call 3-1, which will call 2-1, which will call 1-1, which will print zero, Print any one, and then print another zero as 1-2 is at least 0.  
 So far we have backed up 010 so far for the first time in the "plug-in" recursively.  
 So this is where it confuses me, it does not really return anything, it just prints, so tells printx (2-1), where hell is its Get value? I can think that it can call itself repeatedly and calls it only in a short time, and the base case reaches 4 or 5 different times.   
 
 
 OK, this argument is:  
 PrintX (3) -> gt; ; PrintX (3 - 1)  
 PrintX (2) - & gt; PrintX (2 - 1)  
 PrintX (1) - & gt; PrintX (1 - 1) that prints  ago 0   
 Then printx (1) calls  Print 1  and printx (1 - 2) prints  Second 0 .  
 Then printx calls (2)  2 prints  and printx (2 - 2) that  prints the third one .  
 Then printX (3)  3 prints  and printx (3 - 2)  
 printx (1) - & gt; PrintX (1 - 1) that prints  fourth 0 .  
 Then printX (1)  Print 1  and printX (1 - 2) << Strong> 010203010     <

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