java - How to convert big floats to int -


मैंने java और php में एक प्रोग्राम लिखा था। जिसमें एक लूप चलाता है 64 बार और n से n जोड़ना जारी रखें:

जावा कोड: 

  सार्वजनिक स्थिर शून्य मुख्य (स्ट्रिंग [] आर्ग्स) {डबल एन = 1; डबल पी = 1; के लिए (इंट आई = 1; आई & lt; = 64; i ++) {n = n + n; पी = पी + एन; } System.out.println (p); }   
 PHP कोड:  
  & lt;? php $ n = 1; $ p = 0; ($ i = 1; $ i & lt; = 64; $ i ++) के लिए {$ n = $ n + $ n; $ p = $ p + $ n; } गूंज ($ p); ? & Gt;   
 और इनमें से दोनों का आउटपुट है:  
  3.6893488147419E + 19   
 अब मैं जानना चाहता हूं क्या यह बड़ा फ्लोट को बदलना संभव है? यदि हां, तो कैसे दोनों भाषाओं में।   
 
 
 मैं इस प्रकार का उपयोग करेगा,  
  सार्वजनिक स्थिर शून्य मुख्य (स्ट्रिंग [] आर्ग्स) {BigInteger n = BigInteger.ONE; BigInteger p = BigInteger.ONE; के लिए (int i = 1; i & lt; = 64; i ++) {n = n.add (n); p = p.add (n); } System.out.println (p); }   
 आउटपुट है  
  36893488147419103231   
  संपादित करें  आपकी टिप्पणी के आधार पर, आप वास्तव में कुछ और पसंद करना चाहता था -  
  बिगइन्टेगर n = बिगइंटेर। BigInteger p = BigInteger.ZERO; बिगइंटेगर TWO = नया बिगइन्टेगर ("2"); के लिए (इंट आई = 1; आई & lt; = 64; i ++) {स्ट्रिंगबिइल्डर एस.बी. = नया स्ट्रिंगबिल्डर (); Sb.append ("वर्ग # के लिए:" + i); sb.append (", वर्ग पर अनाज:" + n); p = p.add (n); N = n.multiply (TWO); Sb.append (", कुल रनिंग:" + p); Println (sb.toString ()); }

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