c++ - How to pass an array by reference? -


I'm trying to overcome this array from context but my code is not capable of taking the function. help? 

  #include & lt; Iostream & gt; using namespace std; Zero print (int (and array) [], int lower-bound, int ex-bound); Int main () {// generated array int int = 20; int array [size]; For (int i = 0; i    
 
 
 
 How to pass an array by reference in CPP?   
 You got almost the correct syntax, but you need the size of the array, which you can clearly specify if you only have to support one size:  
  const int SIZE = 20; Zero print (int (and array) [SIZE], int lower-over, array upper-bound);   
 To use this function template to remove it, if you need a function for different sizes:  
  template & lt; Size_t N & gt; Zero printed (Ant and Arrayage) [n], int lower-bend, int extbound) {// code here}   
 Note that there are more idiotic solutions in C ++ To specify and specify the one-past-the-end-enders (plain pointers), others have  std :: arrays  for arrays of fixed size and  std for people with dynamic size :: vector  to use.

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